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NEET Sample Paper NEET Sample Test Paper-79

  • question_answer
    pH of solution prepared by mixing 800 mL of 0.05 N NaOH and 200 mL of 0.1 N HCl assuming the complete ionisation of acid and a base is

    A)  5                                

    B)  10.4

    C)  12.3                            

    D)  1.7

    Correct Answer: C

    Solution :

    Number of mill equivalents of \[\operatorname{NaOH}= 800\,\,\times \,\,0.05 =40\] Number of mill equivalents of HCI \[=\,\,200\times 0.1 =20\] \[\operatorname{Total} volume = 200 + 800 = 1000 mL\] Number of mill equivalents of NaOH present in \[40-20=20\] \[\operatorname{pOH}=-log{{\left[ OH \right]}^{-}}\] \[=-\,log\left[ 2\,\,\times \,\,1{{0}^{-}}^{2} \right]\] \[=\,\,\,1.7\] also \[\operatorname{pH}\,\,+\,\,pOH=14\] \[\operatorname{pH}=14-pOH\] \[=\,\,\,14-1.7=12.3\]


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