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NEET Sample Paper NEET Sample Test Paper-79

  • question_answer
    In an AC circuit, V and I are given by \[\operatorname{V} =100 sin(100\,t)\] volt and \[\operatorname{I} = 100 sin\,\left( 100\,t+\frac{\pi }{3} \right)amp\], the power dissipated in the circuit is

    A)  104 W             

    B)  2.5 kW

    C)  5 kW               

    D)  10 W

    Correct Answer: B

    Solution :

    Here, \[{{V}_{0}}\,\,=\,\,100\,V,\,\,{{I}_{0}}\,\,=\,\,100A\] and phase difference \[\phi =\,\,\frac{\pi }{3}\] \[P={{V}_{rms}}\times {{I}_{rms}}\times \cos \,\,\phi \] \[=\,\,\,\frac{{{V}_{0}}{{I}_{0}}}{2}\,\cos \,\,\phi \] \[=\,\,\,\,\frac{100\times 100}{2}\times \frac{1}{2}\] \[= \,2500 W=2.5 kW\]


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