NEET Sample Paper NEET Sample Test Paper-79

  • question_answer
    A particle of mass M moves in a circular path of radius R under the action of a force \[F=\frac{M{{\nu }^{2}}}{R}\]. The work done by force F during its motion over half of the circumference of the circular path is

    A)  zero                             

    B)  \[\left( \frac{M{{v}^{2}}}{R} \right)\times \pi \,R\]

    C)  \[\left( \frac{M{{v}^{2}}}{2} \right)\,\,\times \,\,2\pi \,R\]           

    D)  None of these

    Correct Answer: A

    Solution :

    The work done by centripetal force is zero.


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