NEET Sample Paper NEET Sample Test Paper-79

  • question_answer
    A cylindrical tube, open at both ends has fundamental frequency V in air. The tube is dipped vertically in water, so that half of it is immersed in water. The fundamental frequency of air column is now

    A)  v                                

    B)  2v

    C)  v/2                              

    D)  3v/4

    Correct Answer: A

    Solution :

    For cylindrical tube open at both ends frequency \[v=\frac{v}{2l}\] When half of tube is immersed in water, its length will be half and also it will behave as a closed pipe. \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\nu '=\frac{v}{4(1/2)}=\frac{v}{2l}\,\,\,\,\,\,\therefore \,\,\,\,\,v'=v\]


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