A) \[\lambda =1.8 cm\]
B) \[\operatorname{v}=4\,\,m{{s}^{-}}^{1}\]
C) \[\operatorname{a} = 0.4 m\]
D) \[f=50\,\,Hz\]
Correct Answer: A
Solution :
The given equation is \[Y=4\,\,\sin \,\left[ \pi \left( \frac{t}{5}-\frac{x}{9}+\frac{1}{6} \right) \right]\] Comparing with standard equation as below \[Y=\,\,a\,\sin \left( \frac{2\pi }{T}t-\frac{2\pi }{\lambda }\cdot x+\phi \right)\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\operatorname{a} =4 cm = 0.04m\] Frequency \[f=\frac{1}{T}=\frac{1}{10}=0.1\,\,Hz\] Wavelength \[\lambda = 2\times 9=18 cm\] Velocity \[\operatorname{v} = v\lambda =0.1 \times 18 = 1.8 cm\]
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