A) 20 h
B) 10 h
C) 7.5 h
D) 5 h
Correct Answer: C
Solution :
\[k=\frac{0.693}{45}\,\,{{\min }^{-\,1}}\] \[=\,\,\,\frac{2.303}{{{t}_{99.9\,%}}}\log \,\frac{a}{a-0.999a}\] \[or\,\,\,\,\,{{t}_{99.9\,%}}\,\,=\,\,\frac{2.303}{0.693}\times \log \,{{10}^{3}}\] \[=\,\,\,448min \approx \,\,7.5 h\]
You need to login to perform this action.
You will be redirected in
3 sec
