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NEET Sample Paper NEET Sample Test Paper-78

  • question_answer
    If the degree of ionisation of water will be \[1.8 \times  1{{0}^{-}}^{9}\] at 298 K, its ionisation constant will be

    A)  \[1.8\,\,\times \,\,1{{0}^{-}}^{16}\]                

    B)  \[1\,\,\times \,\,1{{0}^{-}}^{14}\]

    C)  \[1\,\,\times \,\,1{{0}^{-}}^{16}\]                   

    D)  \[1.67\,\,\times \,\,1{{0}^{-}}^{14}\]

    Correct Answer: A

    Solution :

    \[{{K}_{a}}=\frac{{{K}_{w}}}{[{{H}_{2}}O]}=\frac{{{10}^{-\,4}}}{55.5}=1.8\times {{10}^{-\,16}}\]


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