2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-78

  • question_answer
    Two particles on a wave having wavelength 2m are at the distance of 5m and 9 m respectively from origin. The phase difference between particle is

    A)  \[\pi \]                          

    B)  \[2\pi \]

    C)  \[\frac{\pi }{2}\]                                   

    D)  \[4\pi \]

    Correct Answer: D

    Solution :

    \[\operatorname{Phase} difference =\,\,\frac{2\pi }{\lambda }\times  path difference\] \[\operatorname{Path} difference =9-5=4\] \[Wavelength\,\,\lambda =2\] \[\operatorname{Phase} difference =\,\,\frac{2\pi }{2}\times 4=4\pi \]


You need to login to perform this action.
You will be redirected in 3 sec spinner