A) 72.1 m/s
B) 172.1 m/s
C) 197.2 m/s
D) None of these
Correct Answer: B
Solution :
As, magnitude of velocity v with which the bomb hits the ground is \[\operatorname{v}=\sqrt{{{u}^{2}}+{{g}^{2}}{{t}^{2}}}\] \[=\,\,\,\sqrt{{{(100)}^{2}}+{{(9.8)}^{2}}\times {{\left( \frac{100}{7} \right)}^{2}}}\] \[= \,\,172.1 m/s\]
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