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NEET Sample Paper NEET Sample Test Paper-78

  • question_answer
    The maximum percentage error in the determination of \[\operatorname{g}(g= 4{{\pi }^{2}}l/{{t}^{2}})\], when l and t are measured with \[\pm  2%\] and \[\pm  3\,%\] errors is

    A)  \[2\,%\]                                    

    B)  \[6\,%\]

    C)  \[8\,%\]                        

    D)  None of these

    Correct Answer: C

    Solution :

    As, \[g=4{{\pi }^{2}}\,/{{t}^{2}}\] \[\Rightarrow \,\,\,\,\,\,\,\frac{\Delta \,g}{g}\times 100=\pm \left( \frac{\Delta l}{l}\times 100+\frac{2\Delta t}{t}\times 100 \right)\] \[=\,\,\pm \left( 2+2\times 3 \right)%\] \[=\,\, \pm  8\,%\] So, \[\operatorname{maximum} error = 8\,%\]


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