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NEET Sample Paper NEET Sample Test Paper-78

  • question_answer
    A wire is suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm. Then the elastic energy stored in wire is

    A)  0.2 J               

    B)  10 J                     

    C)  20 J                            

    D)  0.1 J

    Correct Answer: D

    Solution :

    Elastic energy stored in the wire is \[\operatorname{U}= \frac{1}{2} \times  stress\,\,\times strain \times  volume\] \[=\,\,\,\frac{1}{2}\times \frac{F}{A}\times \frac{\Delta \,l}{L}\times AL=\frac{1}{2}F\Delta l\] \[=\,\,\frac{1}{2}\times 200\times 1\times {{10}^{-\,3}}=0.1\,\,J\]


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