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NEET Sample Paper NEET Sample Test Paper-77

  • question_answer
    Equilibrium constant of a chemical reaction is 1.5 and rate constant of forward reaction is\[7.5\,\,\times \,\,1{{0}^{-\,4}}\]. Then, rate constant of backward reaction will be

    A)  \[1.125\,\,\times \,1{{0}^{-\,3}}\]                     

    B)  \[2.225\,\,\times \,1{{0}^{-\,3}}\]

    C)  \[3.335\,\,\times \,1{{0}^{-\,5}}\]         

    D)  \[1.125\,\,\times \,1{{0}^{-\,1}}\]

    Correct Answer: A

    Solution :

    We know that \[{{K}_{C}}=\frac{{{K}_{f}}}{{{K}_{b}}}\,\,\,\Rightarrow \,\,{{K}_{f}}={{K}_{b}}\times {{K}_{c}}\] \[=\,\,\,1.5\times 7.5\times {{10}^{-\,4}}\,\,=\,\,1.125\times {{10}^{-\,3}}\]


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