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NEET Sample Paper NEET Sample Test Paper-77

  • question_answer
                        \[{{\operatorname{NaBH}}_{4}}\] on reaction with \[{{I}_{2}}\] produces a compound X, X on reaction with oxygen produces an anhydride. X on reaction with \[N{{H}_{3}}\] forms an adduct. X is

    A)  \[{{B}_{2}}{{H}_{6}}\]                     

    B)  LiH

    C)  \[B{{H}_{4}}\]                       

    D)  \[IB{{H}_{2}}\]

    Correct Answer: A

    Solution :

    \[LiAI{{H}_{4}} + {{I}_{2}} \xrightarrow{{}}\,\,{{B}_{2}}{{H}_{6}}\] \[{{\operatorname{B}}_{2}}{{H}_{6}}\,+\,\,3{{O}_{2}}\,\,\xrightarrow{{}}\,\,\underset{Boric\,\,anhydride}{\mathop{{{B}_{2}}{{O}_{3}}}}\,\] \[{{\operatorname{B}}_{2}}{{H}_{6}} +N{{H}_{3}} \xrightarrow{{}}\,\,B{{H}_{3}}\cdot N{{H}_{3}}\]


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