question_answer

In \[{{\operatorname{IF}}_{7}}\] molecule, central atom has all the bonded electrons i.e., no lone pair is present on the central atom. Structure of \[{{\operatorname{IF}}_{7}}\] is

A)  pentagonal bipyramidal          

B)  octahedral

C)  square pyramidal                              

D)  octahedral monopyramidal

Correct Answer: A

Solution :

              Structure of \[{{\operatorname{IF}}_{7}}\] is determined by using hybridisation as follows \[H=\frac{V+M-C+A}{2}\,\,=\,\,\frac{7+7}{2}\,\,=\,\,7\] \[\operatorname{Hybridisation} =s{{p}^{3}}{{d}^{3}}\] \[\operatorname{Structure} = Pentagonal bipyramidal\]