A) Carius method
B) Lassaigne's method
C) Kjeldahl's method
D) Duma's method
Correct Answer: A
Solution :
When organic compound is treated with cone. \[HN{{O}_{3}}\] in a carrier tube P present on organic compound can be converted into \[{{\operatorname{H}}_{3}}P{{O}_{4}}\]. Contents of tube is heated with \[\operatorname{MgC}{{l}_{2}}\] in presence of \[{{\operatorname{NH}}_{4}}Cl\] and \[\operatorname{N}{{H}_{4}}OH\]. Then \[\operatorname{MgN}{{H}_{4}}P{{O}_{4}}\] is formed which is dried and weighted. \[P\,\,\to PO_{4}^{3-}\] \[PO_{4}^{3\,-}\,\frac{Mgc{{l}_{2}}}{N{{H}_{4}}Cl+N{{H}_{4}}OH}\,\,MgN{{H}_{4}}P{{O}_{4}}\,\,\xrightarrow{\Delta }\,\,M{{g}_{2}}{{P}_{2}}{{O}_{7}}\]\[%\,P\,\,=\,\,62\,\,\times \,\,\frac{weight\,\,of\,\,M{{g}_{2}}{{P}_{2}}{{O}_{7}}}{222\times weight\,\,of\,\,compound}\,\,\times \,\,100\]
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