A) \[\operatorname{IV}>I>III>II\]
B) \[III>I>II>IV\]
C) \[II > I > III > IV\]
D) \[\operatorname{I} > III > II > IV\]
Correct Answer: B
Solution :
More free the electron present on N atom as a lone pair, more will be its basic strength, In IV lone pair of nitrogen is involved in acromatic 671 electrons, hence IV is least basic among all.
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