A) \[2\text{ }si{{n}^{-}}^{1}\,\left( \frac{3}{4} \right)\]
B) \[si{{n}^{-}}^{1}\,\left( \frac{3}{4} \right)\]
C) \[{{\cos }^{-}}^{1}\,\left( \frac{3}{2} \right)\]
D) \[2\,\,{{\cos }^{-}}^{1}\,\left( \frac{3}{4} \right)\]
Correct Answer: D
Solution :
As, \[\mu =\frac{\sin \left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \,\left( \frac{A}{2} \right)}\] \[\Rightarrow \,\,\,\,\mu =\frac{\sin \left( \frac{A+A}{2} \right)}{\sin \,\left( \frac{A}{2} \right)}\,\,\,\Rightarrow \,\,\,\,\mu =\frac{\sin \,A}{\sin \,\frac{A}{2}}\] \[\Rightarrow \,\,\,\,\,\mu =\frac{2\,\sin \,\frac{A}{2}\,\cos \,\frac{A}{2}}{\sin \,\frac{A}{2}}\,\,=\,\,2\,\,cos\,\,\frac{A}{2}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,A=2\,{{\cos }^{-\,1}}\,\left( \frac{\mu }{2} \right)\] \[\Rightarrow \,\,\,\,\,\,\,\,\,A=2\,{{\cos }^{-\,1}}\,\left( \frac{1.5}{2} \right)\,\,\,=\,\,2\,\,{{\cos }^{-1}}\,\left( \frac{3}{4} \right)\]
You need to login to perform this action.
You will be redirected in
3 sec
