A) \[\sqrt{\frac{2\,H}{g}}\]
B) \[\sqrt{\frac{2\,H}{g}}+\frac{2\,H}{v}\]
C) \[\sqrt{\frac{2\,H}{g}}+\frac{H}{v}\]
D) None of these
Correct Answer: C
Solution :
If \[{{t}_{1}}\] is time taken by stone to reach at level of water then, \[H=0+\frac{1}{2}gt_{1}^{2}\,\,\,\,\,\,\,\,\,\,\,\,\left[ as,\,\,s=ut+\frac{1}{2}a{{t}^{2}} \right]\] \[{{t}_{1}}=\sqrt{\frac{2\,H}{g}}\] Now, time taken by sound to reach at top \[{{t}_{2}}=\frac{H}{v}\] \[\therefore \] Total time \[=\,\,{{t}_{1}}+{{t}_{2}}=\sqrt{\frac{2H}{g}}+\frac{H}{v}\]
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