A) \[-\,{{E}_{0}}\]
B) \[1.5\,\,{{E}_{0}}\]
C) \[2\,\,{{E}_{0}}\]
D) \[{{E}_{0}}\]
Correct Answer: C
Solution :
For a satellite, we have \[\operatorname{Kinetic} energy =\,\,\frac{GmM}{2r}\] \[\operatorname{Potential} energy =\,\,-\frac{GmM}{r}\] Total energy \[{{E}_{0}}= KE + PE\] \[=\,\,\,\frac{GmM}{2r}-\frac{GmM}{r}=-\frac{GmM}{2r}=\frac{PE}{2}\] or \[\operatorname{PE}=2{{E}_{0}}\]
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