A) increases by a factor 20
B) decreases of a factor 20
C) increases by a factor 10
D) decreases by a factor 10
Correct Answer: C
Solution :
Here \[{{\operatorname{V}}_{air}}=350m/s,\,\,{{V}_{gold}}=3500m/s\] as sound travels from one medium to another, frequency remain constant. \[\because \,\,\,\,\,\,\,\,\,\,\,Frequency\,\,\nu =\frac{\nu }{\lambda }\,\,\,\Rightarrow \,\,\frac{{{v}_{air}}}{{{\lambda }_{air}}}=\frac{{{v}_{gold}}}{{{\lambda }_{gold}}}\] \[{{\lambda }_{gold}}={{\lambda }_{air}}\,\times \,\frac{{{v}_{gold}}}{{{v}_{air}}}\,\,=\,\,{{\lambda }_{air}}\times \frac{3500}{350}=10\,\,{{\lambda }_{air}}\]
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