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NEET Sample Paper NEET Sample Test Paper-77

  • question_answer
    A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is

    A)  4pV                            

    B)  2pV

    C)  \[\frac{pV}{2}\]                                   

    D)  pV

    Correct Answer: B

    Solution :

    Work done in cyclic process is equal to the area under the cycle, also work done is positive, if cycle is clockwise and negative if cycle is anticlockwise. In cyclic process \[\Delta U = 0\] By 1st law of thermodynamics \[\Delta O=\Delta U+\Delta W\]                                       ... (i) \[\Delta W=-Area of rectangle\,\,ABCD\] \[=-p(2V)=-\,2pV\] Putting \[\Delta U= 0 \,and\,\,\Delta W = -2 pV\] in Eq. (i) We have \[\Delta Q = \Delta W = -2pV\] (AO heat absorbed) \[\therefore \,\,\,\,Heat rejected by gas =2p\,V\]


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