A) All atomic particles in motion have waves of a definite wavelength associated with them
B) The higher the momentum, the larger is the wavelength
C) The faster the particle, the shorter is the wavelength
D) For the same velocity, a heavier particle has a shorter wavelength
Correct Answer: B
Solution :
\[\lambda =\frac{h}{p}=\frac{h}{mv}\]where, \[\operatorname{h} =Plancks constant, \lambda = wavelength,\] \[\operatorname{p}=mv =momentum\] It is shown that wavelength \[\lambda \] is inversely proportional to the momentum. Hence, lighter the momentum, lesser will be the wavelength. So, statement [b] is not true.
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