2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-76

  • question_answer
    A capillary tube of radius R is immersed in water and water rises in it to a height H. Mass of water in capillary tube is M. If the radius of tube is doubled, mass of water that will rise in capillary will be

    A)  M                               

    B)  \[\frac{M}{2}\]

    C)  2 M                             

    D)  4 M

    Correct Answer: C

    Solution :

    Since,    \[h=\frac{2T\,\cos \,\,\theta }{r\rho h}\,\,i.e.,\,\,h\propto \frac{1}{r}\] As, r changes to 2 r then h will become\[\frac{h}{2}\]. \[\operatorname{Mass} of water in tube = volume \times  density\] \[=\,\,\,\,\,\,\pi {{(2r)}^{2}}\frac{h}{2}\rho \] \[=\,\,\,\,2\left( \pi {{r}^{2}}h\rho  \right) =2\,M\]


You need to login to perform this action.
You will be redirected in 3 sec spinner