A) Urea
B) Sodium dodecyl sulphate
C) Sodium acetate
D) Cetyltrimethylammonium bromide
Correct Answer: D
Solution :
\[R{{(N{{H}_{3}})}_{3}}Br\,\,\xrightarrow{{}}\,\,R(N{{H}_{3}})_{3}^{+}\,\,+\,\,B{{r}^{-}}\] Alkyl trimethyl ammonium ions aggregates to form cationic micelles.
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