A) 0 6
B) N
C) C
D) B
Correct Answer: A
Solution :
Electronic configuration of oxygen is \[1{{s}^{2}}\,2{{s}^{2}}\,2{{p}^{4}}\] \[O(2{{p}^{4}})\xrightarrow{-e}\,O\,(2{{p}^{3}})\,\,\xrightarrow{-e}\,\,O\,(2{{p}^{2}})\] \[\uparrow \] Half filled electronic configuration
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