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NEET Sample Paper NEET Sample Test Paper-76

  • question_answer
    Bond order of CO is equal to bond order of

    A)  \[B{{e}_{2}}\]                        

    B)  \[O_{2}^{+}\]

    C)  \[N_{2}^{+}\]                                   

    D)  \[N_{2}^{{}}\]

    Correct Answer: D

    Solution :

    Bond order of CO is 3 and bond order of \[{{N}_{2}}\] is also 3. It can be easily calculated using formula \[\operatorname{Bond} order =\,\,\frac{Nb-Na}{2}\] where, Nb = number of electrons in BMO. Na = number of electrons in ABMO.


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