A) 5 mH
B) 5 H
C) 50 H
D) - 5 mH
Correct Answer: A
Solution :
\[\frac{dl}{dt}=\frac{(2-3)}{{{10}^{-\,3}}}=-{{10}^{3}}\,A/s\] As, \[e=-L\frac{dl}{dt}\] \[5=-L\left( -{{10}^{3}} \right)\] \[L=\frac{5}{{{10}^{3}}}H=5mH\]
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