A) \[\frac{1}{2}m{{v}^{2}}\]
B) \[\frac{1}{2}{{m}^{2}}v\]
C) \[\frac{1}{2}m{{v}^{3}}\]
D) \[m{{v}^{3}}\]
Correct Answer: C
Solution :
As the mass flowing per unit length is m and velocity of water is v. So, \[\operatorname{mass} flowing per second\,\,=\,\,mv\] Rate at which kinetic energy is imparted to water \[=\,\,\,\,\frac{1}{2}(mv){{v}^{2}}\] \[=\,\,\,\,\frac{1}{2}m{{v}^{3}}\]
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