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NEET Sample Paper NEET Sample Test Paper-75

  • question_answer
    A cylinder containing 1 mole of gas was compressed adiabatically until its temperature rises from 300 K to 370 K. Then, heat produced in the gas is \[\left( given r=1.5 \right)\]

    A)  276.7 cal                     

    B)  376.7 cal             

    C)  298.5 cal                     

    D)  398.5 cal

    Correct Answer: A

    Solution :

    Here initial temperature, \[{{T}_{1}} = 300 K\] Final temperature \[{{\operatorname{T}}_{2}}\, = \,370 K\] If gas is compressed adiabatically, then work done on the gas is \[W=\frac{R}{(1-r)}({{T}_{2}}-{{T}_{1}})\] \[\frac{8.2\times \left( 370-300 \right)}{(1-1.5)}=11.6\times {{10}^{2}}\,J\] \[\operatorname{Heat} produced\,\,H\,\,=\,\frac{W}{J} =\,\,\frac{11.62\times {{10}^{2}}}{4.2}= 276.7 cal\]


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