NEET Sample Paper NEET Sample Test Paper-75

  • question_answer
    A particle is revolving in a circular path completes first half of circumference in 4s and next half in 2s, then the average angular velocity of particle is

    A)  \[\frac{2\pi }{3}rad/s\]              

    B)  \[\frac{\pi }{3}rad/s\]

    C)  \[\pi \,\,rad/s\]               

    D)  \[2\pi \,\,rad/s\]

    Correct Answer: B

    Solution :

    Angular displacement \[{{\theta }_{1}}=\frac{2\pi }{2}=\pi \,\,(first\,\,half)\] Angular displacement \[{{\theta }_{2}}=\frac{2\pi }{2}=\pi \,\,(\sec ond\,\,half)\] and total time \[\operatorname{T} =\left( 4 + 2 \right) s = 6s\] \[\therefore \,\,\,\,\,\,\,\,{{\omega }_{av}}=\frac{{{\theta }_{1}}+{{\theta }_{2}}}{T}=\frac{\pi +\pi }{6}=\frac{2\pi }{6}=\frac{\pi }{3}\,\,rad/s\]


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