A) \[2\times 1{{0}^{7}}m/s\]
B) \[3\times 1{{0}^{8}}m/s\]
C) \[8\times 1{{0}^{7}}m/s\]
D) \[8\times 1{{0}^{10}}m/s\]
Correct Answer: C
Solution :
As, \[\frac{1}{2}m{{v}^{2}}=eV\,\,\,\,\,\,\Rightarrow \,\,\,V=\sqrt{\frac{2eV}{m}}\] Here, \[\operatorname{V}=18kV=18\times 1{{0}^{3}}\,V\] \[e=1.6\times {{10}^{-19}}C\] \[m=9.1\times {{10}^{-31}}kg\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,v=\sqrt{\frac{2\times 1.6\times {{10}^{-19}}\times 18\times {{10}^{3}}}{9\times {{10}^{-\,31}}}}\] \[=\,\,8\times 1{{0}^{7}}m/s\]
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