A) 12
B) 2
C) 8
D) 3
Correct Answer: B
Solution :
If one base is coding one ammo acid, then \[{{\left( 12 \right)}^{1}}=12\] but there are 96 amino acids suppose, two bases form one codon, then\[{{\left( 12 \right)}^{2}}=144\]. This is sufficient to code 96 or 20 amino acids and hence two, bases form one codon.
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