A) \[{{R}^{3/2}}\]
B) \[{{R}^{2}}\]
C) R
D) \[\sqrt{R}\]
Correct Answer: A
Solution :
As given a satellite is orbiting around the earth in a circular orbit of radius from centre of earth, then its period of revolution can be find out by considering its speed given as, Speed of satellite \[v=\sqrt{\frac{GM}{R}}\] \[\therefore \] Its period of revolution is \[=\,\,\,\frac{2\pi R}{v}\] \[=\,\,\,\frac{2\pi }{\sqrt{GM}}{{R}^{3/2}}\]
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