in term of solubility product x\[({{K}_{sp}})\] can be given as
A) \[{{({{K}_{sp}})}^{1/3}}\]
B) \[{{\left( \frac{{{K}_{sp}}}{2} \right)}^{1/3}}\]
C) \[{{\left( \frac{{{K}_{sp}}}{4} \right)}^{1/3}}\]
D) \[{{\left( \frac{{{K}_{sp}}}{2} \right)}^{1/2}}\]
Correct Answer: C
Solution :
\[\operatorname{CaC}{{l}_{2}}\] is an example of tertiary electrolyte \[CaC{{l}_{2}}\,\,=\,\,\underset{s}{\mathop{C{{a}^{2+}}}}\,\,+\,\,\underset{2s}{\mathop{2C{{l}^{-}}}}\,\] \[{{K}_{sp}}=s\times {{(2s)}^{2}}=4{{s}^{3}}\] \[s{{=}^{3}}\sqrt{\frac{{{K}_{sp}}}{4}}={{\left( \frac{{{K}_{sp}}}{4} \right)}^{1/3}}\]
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