A) +2, 5.92 BM
B) +7, 4.83 BM
C) +6, 3.87 BM
D) +7, 5.92 BM
Correct Answer: D
Solution :
Maximum oxidation state of Mn is found in \[\operatorname{KMn}{{O}_{4}}\] is + 7. \[MnO_{4}^{-}\] \[x-2\times 4=-1\] \[\operatorname{x}=-1+8=+7\] \[M{{n}^{2+}}\] state has five unpaired electrons. \[\mu =\sqrt{5\left( 5+2 \right)}=5.92\,\,BM\]
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