A) \[{{\operatorname{CaCO}}_{3}} \xrightarrow{{}} CaO + C{{O}_{2}}\]
B) \[\operatorname{Na}\,\,+\,\,{{H}_{2}}O\,\,\xrightarrow{{}}\,\,NaOH\,\,+\frac{1}{2}\,{{H}_{2}}\]
C) \[{{\operatorname{MnCl}}_{3}}\,\,\xrightarrow{{}}\,\,MnC{{l}_{2}}\,+\,\,\frac{1}{2}C{{l}_{2}}\]
D) \[{{O}_{2}}+2{{H}_{2}}\,\xrightarrow{{}}\,2{{H}_{2}}O\]
Correct Answer: B
Solution :
\[\overset{+\,2\,+}{\mathop{Ca}}\,\overset{4\,-\,2}{\mathop{C{{O}_{3}}}}\, \,\to \,\,\overset{+\,2}{\mathop{Ca}}\,\overset{-\,2}{\mathop{O}}\, + \overset{+}{\mathop{C}}\,{{\overset{4}{\mathop{O}}\,}_{2}}\] Since, there is no change in the oxidation state of element, it is not a redox reaction.
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