A) \[{{\lambda }_{e}}>{{\lambda }_{p}}>{{\lambda }_{\alpha }}\]
B) \[{{\lambda }_{p}}={{\lambda }_{\alpha }}>{{\lambda }_{e}}\]
C) \[{{\lambda }_{p}}<{{\lambda }_{e}}<{{\lambda }_{\alpha }}\]
D) \[{{\lambda }_{\alpha }}<{{\lambda }_{e}}={{\lambda }_{p}}\]
Correct Answer: A
Solution :
The expression for the de-Broglie wavelength is \[\lambda =\frac{h}{p}=\frac{h}{mv}\] i.e., \[\lambda \propto \frac{1}{\sqrt{mE}}\] and \[m >>> E\] Thus, correct order is \[{{\lambda }_{e}}>{{\lambda }_{p}}>{{\lambda }_{\alpha }}\].
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