A) \[\frac{9}{11}\]
B) \[\frac{3}{4}\]
C) \[\frac{81}{121}\]
D) \[\frac{144}{212}\]
Correct Answer: C
Solution :
Given, \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{100}{1}\,\,\,\,i.e.\,\,\,\,\,{{l}_{1}}=100\,k,\,\,{{l}_{2}}=k\] (k is proportionality constant) Intensity at maxima is \[{{l}_{\max }}={{l}_{1}}+{{l}_{2}}+2\sqrt{{{l}_{1}}\,{{l}_{2}}}=100+1+2\sqrt{100\times 1}=121\]Intensity at minima is \[{{l}_{min}}={{l}_{1}}+{{l}_{2}}-2\sqrt{{{l}_{1}}\,{{l}_{2}}}\] \[=\,\,100+1-2\sqrt{100\times 1}=81\] \[\therefore \,\,\,\,\,\,\,\,\frac{{{l}_{\min }}}{{{l}_{\max }}}=\frac{81}{121}\]
You need to login to perform this action.
You will be redirected in
3 sec
