If current is 5 A and is decreasing at the rate of \[{{10}^{3}}\] A/s, then \[{{V}_{B}}-{{V}_{A}}\] will be
A) 20 V
B) 10 V
C) 15 V
D) 5 V
Correct Answer: C
Solution :
Given \[\operatorname{L} =5 mH = 5 \times {{10}^{-3}}\,H\] \[\frac{di}{dt}={{10}^{3}}\,A/s\] \[R=1\,\Omega \] To find The potential difference \[{{V}_{B}}-{{V}_{A}}\] Solution Voltage across inductance \[V=L\frac{di}{dt}=(5\times {{10}^{-3}})\,(1{{0}^{3}})=5\,\,V\] Now, \[{{V}_{A}}-\left( 5\times 1 \right)+15\,\,V+5={{V}_{B}}\] or \[{{V}_{B}}-{{V}_{A}}=15\,\,V\]
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