A) \[4 \times 1{{0}^{3}}m\,\]
B) \[16 \times 1{{0}^{3}}m\,\]
C) \[32 \times 1{{0}^{6}}m\,\]
D) \[64 \times 1{{0}^{6}}m\,\]
Correct Answer: B
Solution :
As, \[{{d}_{\max }}=\sqrt{2hR}\] \[=\,\,\,\sqrt{2\times 6.4\times {{10}^{6}}\times 20}\] \[=\,\,\,\,\,16\times {{10}^{3}}\,m\]
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