NEET Sample Paper NEET Sample Test Paper-74

  • question_answer
    An electromagnetic wave is propagating in medium with relative magnetic permeability 50 and relative dielectric, constant 2. The wave impedance of such medium is                                                       

    A)  \[2000\,\,\Omega \]                   

    B)  \[1883\,\,\Omega \]

    C)  \[1550\,\,\Omega \]                   

    D)  \[1222\,\,\Omega \]

    Correct Answer: B

    Solution :

    \[\operatorname{Given} Relative magnetic permeability = 50\] \[Dielectric constant=2\] To find Wave impedance. Solution The impedance is given as \[Z=\sqrt{\frac{{{\mu }_{r}}\,{{\mu }_{0}}}{{{\varepsilon }_{r}}\,\,{{\varepsilon }_{0}}}}=\sqrt{\left( \frac{{{\mu }_{r}}}{{{\varepsilon }_{r}}} \right)\,\left( \frac{{{\mu }_{0}}}{{{\varepsilon }_{0}}} \right)}\] \[=\,\,\,\sqrt{\frac{50}{2}}\times 376.6\,\Omega \,\,=\,\,1883\,\Omega \]


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