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NEET Sample Paper NEET Sample Test Paper-74

  • question_answer
    A rod of mass m and length l is lying on a horizontal table. The work done to make it stand on one end will be

    A)  2 mgl              

    B)  mgl

    C)  \[\frac{mgl}{2}\]                                  

    D)  \[\frac{mgl}{4}\]

    Correct Answer: C

    Solution :

    Centre of mass of rod will lie at length - \[\therefore  Work done = change in potential energy\] \[=\,\, Final PE - Initial PE\] \[=mg\left( \frac{l}{2} \right)-mg\,(0)=mg\frac{l}{2}\]


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