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NEET Sample Paper NEET Sample Test Paper-74

  • question_answer
    If a wire is suspended vertically from one of its end is stretched by attaching a weight of 200 N to the lower en [d] It stretches the wire by 1 mm, then the potential energy stored in the wire is

    A)  1 J                              

    B)  0.1 J

    C)  0.01 J             

    D)  0.001 J

    Correct Answer: B

    Solution :

    As elastic potential energy \[U=\frac{1}{2}\times stress\times strain\times volume\] \[U=\frac{1}{2}\times \frac{F}{A}\times \frac{\Delta l}{l}\times Al=\frac{1}{2}F\Delta l\] \[=\frac{1}{2}\times 200\times {{10}^{-3}}=0.1\,J\]


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