The contribution from the diode \[{{D}_{2}}\] is/are
A) A, C, E
B) B, D, F
C) A, C, E
D) A, B, C, D, E, F
Correct Answer: B
Solution :
When the diode will be forward biased, then they will conduct. In positive half-cycle, diode \[{{D}_{1}}\] will be forward biased and it will conduct, in negative half-cycle, diode \[{{D}_{1}}\] will be reverse biased and it will be off. But during the negative half-cycle, the diode \[{{D}_{2}}\] will conduct. Hence, the junction diode \[{{D}_{2}}\] will provide output only when it will be forward biased. This is the case for negative half-cycles at B, D and F.
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