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NEET Sample Paper NEET Sample Test Paper-72

  • question_answer
    Entropy change involved in conversion of one mole of liquid water at 373 K to vapour at the same temperature (latent heat of vaporisation of\[\operatorname{water} = 2.257 kJ\,{{g}^{-}}^{1}\]).

    A) \[30.7 J{{K}^{-1}} mol{{e}^{\,-1}}\]

    B)   \[60.3 J{{K}^{-1}} mol{{e}^{\,-1}}\]

    C) \[90.8 J{{K}^{-1}} mol{{e}^{\,-1}}\]

    D)   \[108.9 J{{K}^{-1}} mol{{e}^{\,-1}}\]

    Correct Answer: D

    Solution :

    \[\Delta {{H}_{vap}}=2.257\,\,KJ/g=(2.257\times 18)\,\,kJ\,mol{{e}^{-1}}\] \[=\,\,\,40.626\] \[\Delta {{S}_{vap}}=\frac{40.626}{373}=0.1089\,\,kJ\,\,{{K}^{-\,1}}\,mol{{e}^{-\,1}}\]  


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