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NEET Sample Paper NEET Sample Test Paper-72

  • question_answer
    A solution is obtained by dissolving 12 g of urea (mol. wt. 60) in a litre of water. Another solution is obtained by dissolving 68.4 g of cane sugar (mol. wt. 342) in a litre of water at the same temperature. The lowering of vapour pressure in the first solution is

    A) Same as that of 2nd solution

    B) Nearly one-fifth of the 2nd solution

    C) Double that of 2nd solution

    D) Nearly five times that of 2nd solution

    Correct Answer: B

    Solution :

    We know that heat of vaporisation of water at \[100{}^\circ C\] is 40.6 kJ and that of benzene is 31 kJ at\[80{}^\circ C\]. The amount of heat required to vaporise one mole of liquid at constant temperature is known as heat of vapourisation.


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