2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-72

  • question_answer
    The boiling point of a solution of 0.1050 g of a substance in 15.84 g of ether was found to be \[100{}^\circ C\] higher than that of pure ether. What is the molecular weight of the substance [Molceular elevation constant of ether per\[100\,g=21.6\]]?

    A) 144.50             

    B) 143.18

    C) 140.28             

    D) 146.66    

    Correct Answer: B

    Solution :

    \[m=\frac{{{K}_{b}}\times w\times 1000}{\Delta {{T}_{b}}\times W}=143.18\]


You need to login to perform this action.
You will be redirected in 3 sec spinner