A) 79.42 g/mol
B) 132.32 g/mol
C) 177.42 g/mol
D) 242.32 g/mol
Correct Answer: C
Solution :
Here: \[\Delta {{T}_{b}}=0.323\,\,K\] \[\operatorname{w} = 0.5143 g weight of anthracene.\] \[\operatorname{W}=35 g weight of chloroform\] \[{{\operatorname{K}}_{b}}\,\,= Molal elevation constant \left( 3.9 kg/mol \right)\] \[m=\frac{{{K}_{b}}\times w\times 1000}{W\times \Delta {{T}_{b}}}=\frac{3.9\times 0.5143\times 1000}{0.323\times 35}\] \[= 177.42 g/mol\]You need to login to perform this action.
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