A) \[2\,A\]
B) 3.3. A
C) \[\frac{2}{\sqrt{5}A}\]
D) \[\sqrt{5}\,A\]
Correct Answer: A
Solution :
\[\operatorname{R}=6+4=10\,\Omega \] \[{{X}_{L}}= \omega L =2000 \times 5 \times 1{{0}^{-}}^{3}=\,\,10 \Omega \] \[{{X}_{C}}= \frac{1}{\omega C} =\frac{1}{2000 \times 50 \times 1{{0}^{-}}^{6}}=\,\,10 \Omega \] \[\therefore \,\,\,\,\,\,Z=\sqrt{{{R}^{2}}+{{\left( {{X}_{L}}-{{X}_{C}} \right)}^{2}}}\,\,=\,\,10\,\Omega \] Amplitude of current \[=\,\,{{i}_{0}}=\frac{{{V}_{0}}}{Z}=\frac{20}{10}=2\,A\]
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