A) \[0.2\,\,kg\,\,m{{s}^{-}}^{1}\]
B) \[-0.2\,\,kg\,\,m{{s}^{-}}^{1}\]
C) \[0.1\,\,kg\,\,m{{s}^{-}}^{1}\]
D)
\[-\,0.4\,\,kg\,\,m{{s}^{-}}^{1}\] 
Correct Answer: A
Solution :
If a constant force F is applied on a body for a short interval of time\[\Delta t\], then impulse of this force is\[F\,\,\times \,\,\Delta t\]. From Newton?s second law \[F=ma=m\frac{\Delta \nu }{\Delta t}\] \[\Rightarrow \,\,\,\,\,F\Delta t=m\Delta \nu =\Delta p\] \[\therefore \,\,\,\,\,\,\,\operatorname{Im}pulse,\,\,\,I=\Delta p=m\frac{\Delta x}{\Delta t}\] Given, \[\operatorname{m}= 0.1 kg,\, \frac{\Delta x}{\Delta t} = \frac{4}{2} m/s\] \[\therefore \,\,\,\,\,\,\,\,I=0.1\times \frac{4}{2}=\,\,0.2\,\,kg\,\,m{{s}^{-1}}\]
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